Did you mean to convert | foot-pound force |
to | calorie [15 °C] calorie [I.T.] calorie [nutritional] calorie [thermochemical] |
How many foot-pound force in 1 calorie [15 °C]? The answer is 3.0872876444448. We assume you are converting between foot-pound force and calorie [15 °C]. You can view more details on each measurement unit: foot-pound force or calorie [15 °C] The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot-pound force, or 0.23890295761862 calorie [15 °C]. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and calories. Type in your own numbers in the form to convert the units!
1 foot-pound force to calorie [15 °C] = 0.32391 calorie [15 °C]
5 foot-pound force to calorie [15 °C] = 1.61954 calorie [15 °C]
10 foot-pound force to calorie [15 °C] = 3.23909 calorie [15 °C]
20 foot-pound force to calorie [15 °C] = 6.47818 calorie [15 °C]
30 foot-pound force to calorie [15 °C] = 9.71727 calorie [15 °C]
40 foot-pound force to calorie [15 °C] = 12.95636 calorie [15 °C]
50 foot-pound force to calorie [15 °C] = 16.19545 calorie [15 °C]
75 foot-pound force to calorie [15 °C] = 24.29317 calorie [15 °C]
100 foot-pound force to calorie [15 °C] = 32.39089 calorie [15 °C]
You can do the reverse unit conversion from calorie [15 °C] to foot-pound force, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
15 °C calorie: the amount of energy required to warm 1 g of air-free water from 14.5 °C to 15.5 °C at a constant pressure of 101.325 kPa (1 atm). Experimental values of this calorie ranged from 4.1852 J to 4.1858 J. The CIPM in 1950 published a mean experimental value of 4.1855 J, noting an uncertainty of 0.0005 J.
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